Is there a diminishing return on IIR and IIQ?

Math has been done before and iirc the optimal IR:IQ ratio was about 1.61:1

Getting IQ, of course, is much harder than stacking IR.
When I farm merciless solo on my ranger I have like 75% IQ and 305% IR right now, far from optimal.
Have done some testing and partybuff quantity works quite straight forward.

Example:
You run alone and kill kole in solaris with 0% quantity.
From my experience kole drops 8 items then so we set base drop 8.
This is the base drop number of that specific mob with 0% quantity.

In a party of varying size this would turn into:
partysize : base drop + (base drop x partybonus) = drops
2 : 8 + (8 x 0,5) = 12 items
3 : 8 + (8 x 1,0) = 16 items
4 : 8 + (8 x 1,5) = 20 items
5 : 8 + (8 x 2,0) = 24 items
6 : 8 + (8 x 2,5) = 28 items
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EFFECTIVE QUANTITY

Now how increased quantity on gear works with "diminishing" return
100% quantity on kole kill solo (dont know if this is the rule for all mobs):

kole drops 14 items from my experience with 100% quantiy =
100% quantity from gear = drop - base drop = 14-8 = 6 items

from this we can see that a 100% quantity does not give 2x the base drop so there is a diminishing return.

the diminishing return in this specific case mean the effective quantity increase is:
drops = base + (base * quant * dim)
drops-base = base * quant * dim
14-8 = 8 * quant * dim
6 = 8 * quant * dim
6/(8*quant) = dim
6/(8*1,00) = 0,75 = 75%

So from 100% quantity on gear u will see 100 x 0,75 = 75% more drops than with 0% quantity on Kole.
This mean each quantity point is only worth 0,75 effective quantity at this amount.

Drops = 8 + (8 * 0,75) = 14 items


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Did some testing with 153% quantity on Kole.
Got a total of 15 items now.

drops = base + (base * quant * dim)
drops-base = base * quant * dim
15-8 = 8 * quant * dim
7 = 8 * quant * dim
7/(8*quant) = dim
7/(8*1,53) = 0,57 = 57%

So from 153% quantity on gear u will see 153 x 0,57 = 87,21% more drops than with 0% quantity on Kole.
This mean each quantity point is only worth 0,57 effective quantity at this amount.

Drops = 8 + (8 * 0,8721) = 14,96 -> 15 items

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Quantity on gear combined with quantity from partysize seems to work the way your personal drop after diminishing return multiplied with partybonus.

In a party of varying size this would look like:
partysize: (base + (base x effective quantity)) x (1 + extra partybuff) = drop

2 : (8 + (8 * 0,75)) x (1 + 0,5) = 21 items
3 : (8 + (8 * 0,75)) x (1 + 1,0) = 28 items
4 : (8 + (8 * 0,75)) x (1 + 1,5) = 35 items
5 : (8 + (8 * 0,75)) x (1 + 2,0) = 42 items
6 : (8 + (8 * 0,75)) x (1 + 2,5) = 49 items

In this example the 100% effective quantity (0,75) is used.


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This is only quantity and not rarity.
Numbers may vary slightly up and down as i have no idea at what point the different "diminishing" return values set in and there is alot of rounding up/down when it comes to actual drops ingame.


Would like some input if i have gotten something wrong.






There's a diminishing return to practically every freaking thing in this game.

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