5L --> vorici 6 sockets 5L will be keeped?

I think you guys need a bit of good ol' Vorici off-color rolling shenanigans.


https://youtu.be/NrqcD8dYoSE


TLDR: The Vorici socket number recipe doesn't modify the existing sockets in any way, just adds new ones. You can use this to roll three and four off-color sockets on gloves, boots and helmets at a significantly lower average cost than the standard method using chromes and vorici gem color recipes.

"

Bars wrote:

I think you guys need a bit of good ol' Vorici off-color rolling shenanigans.


https://youtu.be/NrqcD8dYoSE


TLDR: The Vorici socket number recipe doesn't modify the existing sockets in any way, just adds new ones. You can use this to roll three and four off-color sockets on gloves, boots and helmets at a significantly lower average cost than the standard method using chromes and vorici gem color recipes.

good trick. didn't know about that.

"

Bars wrote:

I think you guys need a bit of good ol' Vorici off-color rolling shenanigans.

Yup, this is a very old thread (a necro by my standards) and that method wasn't public knowledge at that time, and I feel soooo dumb for not realizing it when I was doing the socket testing, rofl

Wow that is nice info here, well did know about that off colour, but didn't think it'll work for 5l to 5l/6s ;) ty for necro this thread
GL&HF

this was a good thread. i learnt two new things here. both very useful to know.

You know how sockets link? (Where the links are?)
Good. Top left is first socket, bottom right is 6th.
Vorici bench works as follows:
# of new sockets > # of current sockets:
Add new random sockets to current ones.
# of new sockets < # of current sockets:
remove the highest sockets.

Is a good way to get 4 off colours on boots or something. (still costs 200-300 Jewelers, but it easier than the chrome method, for example getting 2r and 2g on something like rainbow strides costs an average of 800 chromes.)

Jeweler method:
1. 2 sockets. (1 Jew.)
2. 1r 1g (15 Chrom.)
3. 3 sockets (3 Jew.)
4. 3rd socket r or g? Y: => step 5, N: 2 sockets (1 Jew.) and => step 3.
5. 4 sockets (10 Jew.)
4. 4th socket correct? Y: => DONE, N: 3 sockets (3 Jew.) and => step 5.