Labyrinth Switch Puzzle
(More involved math:)
Let's define m1...m7 as above. Now define ni = m(i)+ m(i+1). Thus, n1 = 1001 n2 = 01001 ... n4 = 0001001 We can see that adding n3 + n6 gives us: 00100100+ 10000100 = 10100000 Adding m1 to this gives 10100000+ 11100000 = 01000000 This gives us the pattern to flip a single pillar at position 1, as detailed above. ----------------- However, we can also use another useful pattern. the n patterns let us flip two pillars with two spaces between them, but we can define the h series similarly: hi = n(i)+(ni+3)=m(i)+m(i+1)+m(i+3)+m(i+4) So h1 = 10000010 and h3 = 10100000 So the h pattern gives us a way to flip two pillar which are separated by a single pillar. The last post above was derived using this process as h3 + m1. |
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" Ah, I didn't see that in my google search for solutions, so I thought I'd post my math for other folks. Thank you for the link. |
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