Curses max in party

"

HarukaTeno wrote:

"

CAKE wrote:

trick is in the word''additional''

it does not say ''now enemy can have two curses''

2 + x additional = 3 + x additional = 4 =>

Yeah, right...
And now please re-read OP again.
In short, he asks, "will the monsters have THREE curses if HE and HIS FRIEND both have ONE Doedre's ring"?

Answer is (probably) NO.
Monsters could be affected by either
2 curses from player A
or
2 curses from player B
(or maybe 1+1)
BUT NOT by THREE curses at once. Curses don't "stack" like that in party.

Am i wrong?

What do you not understand from my quote?

6players =1 curse + 2x additional[2rings] = 3curses

I tested it before posting

Only if 1 player has both rings on will you get 3 curses on monsters. Until the player with 1 curse replaces those 3 with his 1. What does 6 players have to do with it?

"

CAKE wrote:

What do you not understand from my quote?

6players =1 curse + 2x additional[2rings] = 3curses

And what did you not understand from mine, hmmm?

In very easy words, again.

Player A and player B form a party.
Player A has ONE Doedre's ring AND player B has ONE Doedre's ring.
One ring.
Each of them.
Monsters can be affected by ONLY TWO CURSES AT THE TIME in this case, and never by THREE (as OP enquired).

P.S. if both players would have TWO Doedre's rings EACH - only then monsters could be cursed by three curses simultaneously