Unexiting with binary outcomes?
How does Unexiting work with binary outcomes? For example if i use Iron Fortress with the Runegraft that makes the unlucky spellblock unexiting, whats the middle result? It's either or, there is no middle outcomes here, does it roll wichever is rolled 2 or 3 times?
Last bumped on Jul 23, 2025, 4:18:44 PM
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The middle result is still the middle result.
Logically: you remove the best result and the worst result, and use what remains. Functionally: you aren't rolling a binary outcome. You roll a number, compare that number to the success probability, and derive the binary result from that. With an Unexciting roll, you take the middle numeric roll, and compare that to the probability. |
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I think i don't get it, if i remove the best and worst result on block i remove blocking and not blocking, whats remaining numerically? Can you give an example for lets say 75% unexiting block?
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I don't... think you're processing how Lucky/Unlucky works?
Think of it like this - every hit against you rolls a d100 against your block chance. If the result is higher than your block chance, the enemy hits - if it's lower, it gets blocked. Lucky and Unlucky apply to that - with Iron Fortress, you have "Chance to Block Spell Damage is Unlucky", so the dice is rolled twice and the worse result for you - in this case, the higher roll - is used. E.G. rolling 48 and 65 vs 50% block chance, the spell would hit because it drops the 48. With Unexciting rolls, that dice is rolled three times, and the highest and lowest rolls are both discarded. In this case, rolling 12, 48 and 65 vs 50% block chance would drop the 12 and the 65, meaning the spell rolls a 48 and is thus blocked. |
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" If you roll three times and fail all three times, you remove the best (first fail) and the worst (second fail), and use the remaining (third fail). If you roll three times and fail one time, you remove the best (first success) and the worst (first fail), and use the remaining (second success). If you want a numeric example of it with 75% Unexciting block: By my understanding, these things have you roll between 0 and 1, and it's a success if the result is less than the chance of success--so, rolling less than 0.75 is a success with 75% to succeed, rather than rolling under 0.25 being a failure with 75% chance to succeed. Using that as a basis: If you roll three times and get 0.8, 0.85, and 0.9, you remove the best (0.8) and the worst (0.9) and use the middle (0.85). 0.85 is not less than 0.75, so the block fails. If you roll three times and get 0.2, 0.5, and 0.8, you remove the best (0.2) and the worst (0.8), and use the middle (0.5). 0.5 is less than 0.75, so the block succeeds. Regarding the actual success chance...while I somewhat remember the math for this (cumulative binomial distribution), I can't quickly remember how to calculate it myself, so I stuck this into an excel sheet: =BINOMDIST(1;3;0.25;1) Result: 0.84375 There is an 84.375% chance of failing fewer than 2 out of 3 block rolls with 75% chance to block, meaning that your Unexciting block will be a successful block. You can look at how changing your block chance will affect the overall Unexciting block chance by opening a spreadsheet on Google Sheets, and stick in the above formula (including the =), and changing the 0.25 chance of failure. Last edited by Jadian#0111 on Jul 22, 2025, 9:03:09 PM
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" Never seen it like that but this makes perfect sense, ty |
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